2304=(8x)^2

Solution for 2304=(8x)^2 equation:

2304=(8x)^2

We move all terms to the left:

2304-((8x)^2)=0

determiningTheFunctionDomain
-8x^2+2304=0

a = -8; b = 0; c = +2304;
Δ = b2-4ac
Δ = 02-4·(-8)·2304
Δ = 73728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{73728}=\sqrt{36864*2}=\sqrt{36864}*\sqrt{2}=192\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-192\sqrt{2}}{2*-8}=\frac{0-192\sqrt{2}}{-16}
=-\frac{192\sqrt{2}}{-16}
=-\frac{12\sqrt{2}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+192\sqrt{2}}{2*-8}=\frac{0+192\sqrt{2}}{-16}
=\frac{192\sqrt{2}}{-16}
=\frac{12\sqrt{2}}{-1}
$